upstream test with zeromatrix overloads

Author: ChrisRackauckas

Project.toml

@@ -15,12 +15,12 @@ Statistics = "10745b16-79ce-11e8-11f9-7d13ad32a3b2"
 ZygoteRules = "700de1a5-db45-46bc-99cf-38207098b444"
 
 [compat]
-ArrayInterface = "1.2, 2.0"
+ArrayInterface = "2.7"
 RecipesBase = "0.7, 0.8, 1.0"
 Requires = "0.5, 1.0"
 StaticArrays = "0.10, 0.11, 0.12"
 ZygoteRules = "0.2"
-julia = "1"
+julia = "1.3"
 
 [extras]
 Test = "8dfed614-e22c-5e08-85e1-65c5234f0b40"

src/array_partition.jl

@@ -296,6 +296,7 @@ common_number(a, b) =
 
 ## Linear Algebra
 
+ArrayInterface.zeromatrix(A::ArrayPartition) = ArrayInterface.zeromatrix(reduce(vcat,vec.(A.x)))
 LinearAlgebra.ldiv!(A::LinearAlgebra.LU,b::ArrayPartition) = ldiv!(A,Array(b))
 LinearAlgebra.ldiv!(A::LinearAlgebra.QR,b::ArrayPartition) = ldiv!(A,Array(b))
 LinearAlgebra.ldiv!(A::LinearAlgebra.SVD,b::ArrayPartition) = ldiv!(A,Array(b))

test/upstream.jl

@@ -1,11 +1,11 @@
-using OrdinaryDiffEq, NLsolve, RecursiveArrayTools, Test
+using OrdinaryDiffEq, NLsolve, RecursiveArrayTools, Test, ArrayInterface
 function lorenz(du,u,p,t)
     du[1] = 10.0*(u[2]-u[1])
     du[2] = u[1]*(28.0-u[3]) - u[2]
     du[3] = u[1]*u[2] - (8/3)*u[3]
 end
 u0 = ArrayPartition([1.0,0.0],[0.0])
-@test u0 .* u0' .* false isa Matrix
+@test ArrayInterface.zeromatrix(u0) isa Matrix
 tspan = (0.0,100.0)
 prob = ODEProblem(lorenz,u0,tspan)
 sol = solve(prob,Tsit5());