1+ {
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3+ "name" : " " ,
4+ "signature" : " sha256:9895a0f3fc78aa13cc793dfc60b4d616a3af11e4983465d122ac29be7197893e"
5+ },
6+ "nbformat" : 3 ,
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8+ "worksheets" : [
9+ {
10+ "cells" : [
11+ {
12+ "cell_type" : " heading" ,
13+ "level" : 1 ,
14+ "metadata" : {},
15+ "source" : [
16+ " Chapter 25: Elements of Electro-Mechanical Energy Conversion"
17+ ]
18+ },
19+ {
20+ "cell_type" : " heading" ,
21+ "level" : 2 ,
22+ "metadata" : {},
23+ "source" : [
24+ " Example Number 25.1, Page Number:876"
25+ ]
26+ },
27+ {
28+ "cell_type" : " code" ,
29+ "collapsed" : false ,
30+ "input" : [
31+ " import math\n " ,
32+ " \n " ,
33+ " #variable declaration\n " ,
34+ " sod=15#stator-core outer diameter\n " ,
35+ " sid=10.05#stator-core inner diameter\n " ,
36+ " rod=10.00#rotor-core outer diameter\n " ,
37+ " rid=5#rotor-core inner diameter\n " ,
38+ " a=8#axial lenght of the machine\n " ,
39+ " b=1.20\n " ,
40+ " ur=1000\n " ,
41+ " #calculations\n " ,
42+ " vs=(3.14/4)*((sod*sod)-(sid*sid))*a#volume of stator-core\n " ,
43+ " vr=(3.14/4)*((rod*rod)-(rid*rid))*a#volume of rotor-core\n " ,
44+ " va=(3.14/4)*((sid*sid)-(rod*rod))*a#volume of air-gap in the machine\n " ,
45+ " ed=(.5*b*b)/(4*3.14*math.pow(10,-7))\n " ,
46+ " e=ed*va*math.pow(10,-6)\n " ,
47+ " edm=(.5*b*b)/(4*3.14*math.pow(10,-7)*ur)\n " ,
48+ " es=edm*vs*math.pow(10,-6)\n " ,
49+ " er=edm*vr*math.pow(10,-6)\n " ,
50+ " kr=(vs+vr)/vs\n " ,
51+ " ke=(es+er)/e\n " ,
52+ " ratio=kr/ke\n " ,
53+ " eratio=e/(es+er)\n " ,
54+ " \n " ,
55+ " #result\n " ,
56+ " print \" Energy stored in air gap= \" ,e,\" Joules\"\n " ,
57+ " print \" Energy stored in stator-core= \" ,round(es,2),\" Joules\"\n " ,
58+ " print \" Energy stored in rotor core= \" ,er,\" Joules\"\n " ,
59+ " print \" Ratio of energy dtored in air-gap to that stored in the cores=\" ,round(eratio)\n "
60+ ],
61+ "language" : " python" ,
62+ "metadata" : {},
63+ "outputs" : [
64+ {
65+ "output_type" : " stream" ,
66+ "stream" : " stdout" ,
67+ "text" : [
68+ " Energy stored in air gap= 3.609 Joules\n " ,
69+ " Energy stored in stator-core= 0.45 Joules\n " ,
70+ " Energy stored in rotor core= 0.27 Joules\n " ,
71+ " Ratio of energy dtored in air-gap to that stored in the cores= 5.0\n "
72+ ]
73+ }
74+ ],
75+ "prompt_number" : 2
76+ },
77+ {
78+ "cell_type" : " heading" ,
79+ "level" : 2 ,
80+ "metadata" : {},
81+ "source" : [
82+ " Example Number 25.2, Page Number:877"
83+ ]
84+ },
85+ {
86+ "cell_type" : " code" ,
87+ "collapsed" : false ,
88+ "input" : [
89+ " import math\n " ,
90+ " \n " ,
91+ " #variable declaration\n " ,
92+ " n=800#turns\n " ,
93+ " area=5*5#cross sectional area\n " ,
94+ " i=1.25#amp\n " ,
95+ " x=0.25#cm\n " ,
96+ " l=0.402\n " ,
97+ " #calculations\n " ,
98+ " p=4*3.14*10**(-7)*area*10**(-4)/(0.5*10**(-2))\n " ,
99+ " l=n**2*p\n " ,
100+ " em=.5*i*i*l\n " ,
101+ " W=-1*0.5*n**2*4*3.14*10**(-7)*area*10**(-4)*i**2/(0.5*10**(-2))**2\n " ,
102+ " \n " ,
103+ " #result\n " ,
104+ " print \" a)i)coil inductance=\" ,l,\" H\"\n " ,
105+ " print \" ii)field energy stored=\" ,em,\" J\"\n " ,
106+ " print \" b)mechanical energy output=\" ,W,\" NW\" "
107+ ],
108+ "language" : " python" ,
109+ "metadata" : {},
110+ "outputs" : [
111+ {
112+ "output_type" : " stream" ,
113+ "stream" : " stdout" ,
114+ "text" : [
115+ " a)i)coil inductance= 0.40192 H\n " ,
116+ " ii)field energy stored= 0.314 J\n " ,
117+ " b)mechanical energy output= -62.8 NW\n "
118+ ]
119+ }
120+ ],
121+ "prompt_number" : 13
122+ },
123+ {
124+ "cell_type" : " heading" ,
125+ "level" : 2 ,
126+ "metadata" : {},
127+ "source" : [
128+ " Example Number 25.4, Page Number:882"
129+ ]
130+ },
131+ {
132+ "cell_type" : " code" ,
133+ "collapsed" : false ,
134+ "input" : [
135+ " #variable declaration\n " ,
136+ " lo=50#mH\n " ,
137+ " xo=0.05#cm\n " ,
138+ " r=0.5#ohm\n " ,
139+ " x=0.075#cm\n " ,
140+ " i2=3#A\n " ,
141+ " x2=0.15#cm\n " ,
142+ " \n " ,
143+ " #calculation\n " ,
144+ " l1=2*lo/(1+(x/xo))\n " ,
145+ " lambda1=l1*i2*10**(-3)\n " ,
146+ " W=0.5*l1*i2**2*10**(-3)\n " ,
147+ " l2=2*lo/(1+(x2/xo))\n " ,
148+ " lambda2=l2*i2*10**(-3)\n " ,
149+ " w2=0.5*i2*(lambda1-lambda2)\n " ,
150+ " \n " ,
151+ " #result\n " ,
152+ " print \" a)magnetic stored energy=\" ,W,\" J\"\n " ,
153+ " print \" b)change in magnetic stored energy=\" ,w2,\" J\" "
154+ ],
155+ "language" : " python" ,
156+ "metadata" : {},
157+ "outputs" : []
158+ },
159+ {
160+ "cell_type" : " heading" ,
161+ "level" : 2 ,
162+ "metadata" : {},
163+ "source" : [
164+ " Example Number 25.5, Page Number:883"
165+ ]
166+ },
167+ {
168+ "cell_type" : " code" ,
169+ "collapsed" : false ,
170+ "input" : [
171+ " #variable declaration\n " ,
172+ " rc=0.5#ohm\n " ,
173+ " v=3#V\n " ,
174+ " i=6#A\n " ,
175+ " l1=40#mH\n " ,
176+ " l2=25#mH\n " ,
177+ " wfld=0.5*l2*i*i*0.001\n " ,
178+ " delE=0.5*i*i*0.001*(l1-l2)\n " ,
179+ " \n " ,
180+ " #result\n " ,
181+ " print \" a)magnetic stored energy=\" ,wfld,\" J\"\n " ,
182+ " print \" b)change in magnetic store energy=\" ,delE,\" J\" "
183+ ],
184+ "language" : " python" ,
185+ "metadata" : {},
186+ "outputs" : [
187+ {
188+ "output_type" : " stream" ,
189+ "stream" : " stdout" ,
190+ "text" : [
191+ " a)magnetic stored energy= 0.45 J\n " ,
192+ " b)change in magnetic store energy= 0.27 J\n "
193+ ]
194+ }
195+ ],
196+ "prompt_number" : 3
197+ },
198+ {
199+ "cell_type" : " code" ,
200+ "collapsed" : false ,
201+ "input" : [],
202+ "language" : " python" ,
203+ "metadata" : {},
204+ "outputs" : []
205+ }
206+ ],
207+ "metadata" : {}
208+ }
209+ ]
210+ }
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